Asking a girl on a second date.

Sounds like a problem easily solvable by a brute force algorithm

yeah

a^2 + b^2 = c^2

1/2 a b = 666,666

whats the third equation, i haven't done trig in a long ass time

Sounds like a problem easily solvable by a brute force algorithm

You just have to write one to generate pythagorean triples...

oh or you can program and cheat instead of doing it the old fashioned way

there's no third easy equation to generate pythagorean triples ayz

i feel like we could use the law of cosines or something for a third equation but i forgot all of that shit

You just have to write one to generate pythagorean triples...

All the problem comes down to is finding factors of 1333332

okay, so it should be easy tehn

Waste of space.

all the numbers should be integers

if you don't get the idea of pythagorean triples

Since you are looking for integers, your answer is

A:693
B:1924
C:2045

:sunny:

i wrote a script to do this a long time ago

just figured i'd throw it out since i'm bored

what the fuck

Ok here's another one.

Let's say we have a socially awkward dumbass detector. It detects whether or not you are a Mormon with 99% accuracy. So obviously 1% of the time it returns the wrong answer.

If we use this detector on a random American, and it indicates that the individual s indeed a Mormon, what is the probability of that person actually being a Mormon?

(this is serious btw)

99%

Read the first post, then jump to this page and read the post above me. The train obiviously went off the tracks somewhere in 24 pages. I love TW.

Ok here's another one.

Let's say we have a socially awkward dumbass detector. It detects whether or not you are a Mormon with 99% accuracy. So obviously 1% of the time it returns the wrong answer.

If we use this detector on a random American, and it indicates that the individual s indeed a Mormon, what is the probability of that person actually being a Mormon?

(this is serious btw)

depends on the number of mormons in the US.

99%

Obviously not or I wouldn't have asked the question.

yeah

a^2 + b^2 = c^2

1/2 a b = 666,666

whats the third equation, i haven't done trig in a long ass time

P+B= poopy p

Ok here's another one.

Let's say we have a socially awkward dumbass detector. It detects whether or not you are a Mormon with 99% accuracy. So obviously 1% of the time it returns the wrong answer.

If we use this detector on a random American, and it indicates that the individual s indeed a Mormon, what is the probability of that person actually being a Mormon?

(this is serious btw)

uh this is just 1 - probability of a false positive type 1 error

im not gonna actually do the stats calculation for you though